Answer to Question #135405 in Organic Chemistry for April

Question

A solution is made by dissolving 513 grams of sucrose (C12H22O11) in 2 liters of water. Calculate the mole fraction of each component in the solution. Molar mass of sucrose = 342 g/mol, water = 18 g/mol.

Answer 1

 513 grams of sucrose Have moles = 513 / 342 = 1.5 moles .

 2 liters of water have 2000 ml of wate .

density of water is 1 g / ml .

so , mass of water = 2000 g .

moles of water = 2000 / 18 = 111.11 mol .

So , mole fraction of sucrose = moles of sucrose / total moes of solution .

= 1.5 / 1.5 + 111.11

= 0.013320 .

mole fraction of water = 1 - mole fraction of sucrose = 1- 0.013320 = 0.98667