Question #134689
A protein sample is analyzed by a kjeldahl process during which ammonia is formed. Ammonia
formed is titrated coulometrically with electrogenerated hypobromite (OBr). If the titration is
performed using 19.3 milliamperes current and end point occur at 2 minutes. Calculate the
milligrams of protein present in the sample if one gram of protein nitrogen is contained in each
6.25gof protein (H=1 and N=14).
1
Expert's answer
2020-09-24T11:21:36-0400

Equivalent mass of NH3 17 g (NH3 is monobasic)

m=ZITm = ZIT

for NH3 , z=17gfaradeyz= \frac{17g}{faradey}


=17g96500c= \frac{17g}{96500c}


Mass deposited == 17g96500c×19.3×10\frac{17g}{96500c}\times 19.3\times10 -3A×2×60A\times2\times60 sec


=0.408×10= 0.408\times10 -3g


In NH3 17 g contains 3g of H and 15 g of N


17g NH3 -------------- 15g N


1g NH3 ----------------157N\frac{15}{7}N


NH3 ---------------- 0.36×10\times 10 -3N


0.36×10\times 10 -3N contain in 6.25×\times 0.36×10\times 10 -3g protein

=6.25×0.36= 6.25\times0.36 mg protein

=2.25mg= 2.25 mg protein


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