Answer to Question #134181 in Organic Chemistry for Vero Elo

Question

Approximately 12 billion kilograms of phosphoric acid (H3PO4) are produced annually for fertilizers, detergents, and agents for water treatment. Phosphoric acid can be prepared by heating the mineral fluoroapatite (Ca5(PO4)3F) with sulphuric acid in the presence of water.
Ca5(PO4)3F + 5H2SO4 + 10H2O 3H3PO4 + 5CaSO4.2H2O + HF
If every kilogram of fluoroapatite yields 396 g of phosphoric acid, what is the percent yield?

Answer 1

Ca5(PO4)3F + 5H2SO4 + 10H2O -----------------> 3H3PO4 + 5CaSO4.2H2O + HF

   504.3 g                                                                294 g

   1 x 10³ g                                                              ??

504.3 g Ca5(PO4)3F  ----------------> 294 g H3PO4

1000 g Ca5(PO4)3F ---------------->         ??

theoretical yield of H2PO4 = $1000\times \frac{294}{504.3}$

                                          = 582.986 g

     actual yield = 396 g

percent yield = $\frac{396}{582}\times 100$

                     =

$percent yield = 68.04$ %