Question #133536

Ions B and C react to formthe complex BC. If 35.0 mL of 1.00MB is combined with 35.0mL of 1.00M
C, 0.00500 mol of BC is formed. Determine the equilibrium constant for this reaction.

Expert's answer

After mixing together: B + C = BC

volume is 70 ml

mole of BC is 0.00500

molea of B and C are equal 0.035*1 - 0.005 = 0.030

concentrations are [BC] = 0.005/0.070 = 0.0714 M,

[B] = [C] = 0.030/0.070 = 0.4286 M

Equilibrium constant is

K = [BC]/([B]*[C]) = 0.3887


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