heat of combustion value of 3329 kJmol-1
Let Moles of fuel = ( 0.44 / M ) MOLE .
WHERE M IS MOLAR MASS OF FUEL .
So ., Total Energy = 3329 * 1000 * (0.44 / M .) J .
This Enegy Utilise By The Water = ( 200 ) * ( 4.2 ) * 19.9 J = 16716 j .
Total Energy = This Enegy Utilise By The Water .
3329 * 1000 * (0.44 / M .) J = 16716 J .
So , M = ( 3329 * 1000 * 0.44 ) / 16716
So , M = 87.62 g / mol .
Molar Mass of Gas = 87.6 g / mol.
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