Answer to Question #126588 in Organic Chemistry for Alice

Question

Calculate E tot for the electrochemical cells for A. Fe - Fe^+2 and Cu- CU

B. Zn - Zn^+2 and Ag- Ag

Answer 1

A. E₀(Fe/Fe²⁺) = -0,44 V = Е_а

E₀(Cu/Cu²⁺) = 0,34 V = Е_с

E = E_c - E_a = 0,34 + 0,44 = 0,78 V

B. E₀(Zn/Zn²⁺) = -0,763 V = E_a

E₀(Ag/Ag⁺) = 0,799 V = E_c

E = E_c - E_a = 0,799 + 0,763 = 1,562 V

a = anode

c = cathode