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Answer to Question #125886 in Organic Chemistry for Cameron Hicks

Question #125886
I am using 11.4mg of substrate mixed with .0.0114 mg of Enzyme, how much Buffer should I use to control the pH, 57ml??
1
Expert's answer
2020-07-10T05:25:04-0400

(0.0114 / 11.4) / 0.05 = 0.02 l = 20 ml.

Answer: 20 ml (of 0.05 M buffer)


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