Answer to Question #125886 in Organic Chemistry for Cameron Hicks

Organic Chemistry

Question #125886

I am using 11.4mg of substrate mixed with .0.0114 mg of Enzyme, how much Buffer should I use to control the pH, 57ml??

Expert's answer

(0.0114 / 11.4) / 0.05 = 0.02 l = 20 ml.

Answer: 20 ml (of 0.05 M buffer)

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