Question

give reaction mechanism of acid chloride with gilman reagent.

Answer 1

RCOCl + R₂CuLi $\implies$R₂C(O^-)Cl $\implies$ RCOR

-Cl^- A good leaving group

R₂CuLi behave as a nucleophile and attack on carbon of carbonyl group.

Ketone will formed as final product.

R₂CuLi is a weak nucleophile so it will not attack on further on carbonyl group of Ketone.

RCOCl carbonyl group has more positive charge so R₂CuLi easily attacks on it due to more positive charge of carbon of -COCl.