Answer to Question #124586 in Organic Chemistry for Nyarko Benjamin

Question

Given a 0.1M aqueous solution each of NH4Cl and CH3COONa(ammonium ethanoate),state and explain which of them you would expect to have a lower pH.

Answer 1

Alternatively

For NH₄Cl

$$pH = 1/2(pkw - pKb - logC)$$

For CH₃COONa

pOH = 1/2(pKw - p^Ka - logC)

p^H = 14 - p^OH

CH₃COOH and NH₄OH have same p^Ka and p^Kb that is 4.7447.