Initial
pressure of oxygen(P1)=220 mm of Hg
Pressure in atmosphere=220/760=22/76 atm
Volume of oxygen(V1)=4.0 L
Number of mole of oxygen(n1)=2.0
What will be the pressure(P2) when
Volume of oxygen(V2)=5.0 L
Number of mole(n2)=3.0
According to ideal gas equation
PV=nRT
Temperature is constant
PV/Rn=T
P1V1/Rn1=P2V2/Rn2
P2= P1V1Rn2/Rn1V2
= 22×4×3 ÷ 76×2×5
= 0.34736842105 atm
P2= 264 mm of Hg
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