Solution.
In the first pair, the first compound is the most stable, since the carbation is unstable if the positive charge is at the carbon atom that contains the acceptor group.
In the second pair of particles, the second is the most stable, since the chlorine pulls the electron density on itself, thereby destabilizing the radical if the unpaired electron is in the b-position relative to the chlorine.
Answer:
a) - 1
b) - 2
Comments
Leave a comment