Answer to Question #115690 in Organic Chemistry for Marie Liberty Faye Allauigan

Question

Find the number of milliliters of a solution which contains 0.2000 mole BaCl2 in 500 ml solution that is needed to precipitate SO4-2 as BaSO4 from 3 mM Al2(SO4)3?

Answer 1

Al₂(SO₄)₃ + 3BaCl₂ = 3BaSO₄ + 2AlCl₃

C(BaCl₂) = 0.2/0.5 = 0.4 M

n(SO₄^2-) = 3*3/1000 = 0.009 mol

n(BaCl₂) = 0.009 mol

V(BaCl₂) = 0.009/0.4 = 0.0225 L = 22.5 mL