25 ml AgNO3 reacts with 5 mM NaCl; 35 ml of the silver solution is required to titrate a sample of ZnCl2∙6H2O. How many milligrams of the hydrate are present in the sample?
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Expert's answer
2020-05-13T14:19:33-0400
25 ml AgNO3 reacts with 5 mM (Cl-)
"{\\frac {25}{5}}={\\frac {35}{x}}"
x = 7 mM.
n(ZnCl2*6H2O) = 7/2 = 3.5 mmol.
m(ZnCl2*6H2O) = 3.5*(65+71+6*18)/1000 = 0.854 g = 854 mg
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