25 ml AgNO3 reacts with 5 mM NaCl; 35 ml of the silver solution is required to titrate a sample of ZnCl2∙6H2O. How many milligrams of the hydrate are present in the sample?
1
Expert's answer
2020-05-13T14:19:33-0400
25 ml AgNO3 reacts with 5 mM (Cl-)
"{\\frac {25}{5}}={\\frac {35}{x}}"
x = 7 mM.
n(ZnCl2*6H2O) = 7/2 = 3.5 mmol.
m(ZnCl2*6H2O) = 3.5*(65+71+6*18)/1000 = 0.854 g = 854 mg
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult.
You can find this expert in "Assignmentexpert.com" with confidence.
Exceptional experts! I appreciate your help. God bless you!
Comments
Leave a comment