Solution:
The Williamson Ether Synthesis is an SN2 reaction between a deprotonated alcohol [“alkoxide”] and an alkyl halide that forms an ether.
Methyl and primary alkyl halides are excellent substrates for the Williamson Ether reaction.
The reaction of RO– with an alkyl halide is always going to be much faster than the reaction of ROH because of the higher electron density on the nucleophile (oxygen). That’s why RO– is used.
Therefore,
The best way to prepare CH3OCH(CH3)2 by an SN2 reaction is (4) CH3I and NaOCH(CH3)2.
Answer: (4) CH3I + NaOCH(CH3)2
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