Answer to Question #110117 in Organic Chemistry for derrick

Question

Compound A, C6H12, was found to be optically active. On catalytic reduction over a palladium catalyst, one equivalent of hydrogen was absorbed, yielding compound B, C6H14. When compound A was treated with KMnO4 in an acidic condition, CO2 bubbled out and compound C was formed. Compound C has the formula C5H10O2 and it is an optically active carboxylic acid. Draw the condensed structural formula and state the IUPAC name of compound A, B and C.

Answer 1

The compound A is a terminal alkene since its oxidation by acidic KMnO₄ gives CO₂. There is only one terminal alkene with a chiral Carbon and formula C₆H₁₂. It is 3-methylpent-1-ene.