Reaction:
2HCl = H2 + Cl2
from the equation we can find out:
n(H2) = n(Cl2) = "{\\frac {n(HCl)} {2}}"
In same conditions molar volumes of gases are same too, and if n*Vm = V then
"{\\frac {V(H_2)} {V_m}}= {\\frac {V(Cl_2)} {V_m}}= {\\frac {V(HCl)} {2V_m}}"
"V(H_2)=V(Cl_2)= {\\frac {V(HCl)} {2}}={\\frac {20} {2}}=10" litres
V(H2) = 10 litres
V(Cl2) = 10 litres
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