Answer to Question #106762 in Organic Chemistry for Kadee Morris

Question

Calculate the concentration of buffer components present in 263.00 mL of a buffer solution that contains 0.250 M NH4CL and 0.250 M NH2 immediately after the addition of 1.70 mL of 6.00 M HNO3 ?
Updated 42 mins ago:
What is
NH3 in M?
NH4 in M?

Answer 1

n₁ (NH₃) = n₁ (NH₄⁺) = 263 × 0.250 / 1000 = 0.06575 mol

n (HNO₃) = 6 × 1.7 / 1000 = 0.0102 mol

V₂ = 263 + 1.7 = 264.7 mL = 0.2647 L

n₂ (NH₃) = n₁ (NH₃) - n (HNO₃) = 0.06575 - 0.0102 = 0.05555 mol

n₂ (NH₄⁺) = n₁ (NH₄⁺) + n (HNO₃) = 0.06575 + 0.0102 = 0.07595 mol

C = n / V

C (NH₃) = 0.05555 / 0.2647 = 0.209 M

C (NH₄⁺) = 0.07595 / 0.2647 = 0.287 M