Question

5grams of CaCO3 reacts completely with excess HCL for 2 minutes, find the rate of reaction in grand per hour

Answer 1

$2 minutes (\frac{1 hour}{60 minutes}) =\frac{1}{30} h$

$Rate = \frac{\Delta m(CaCO_3)}{\Delta Time} = \frac{5 grams}{\frac{1}{30} h} =150 g/h$