Question #106365
Calculate the entropy change at 25°C for the following reaction:
Li (s) + 0.5 O2 (g) + 0.5 H2 (g) → LiOH (s).
The entropy contents of the reactants and product at 25°C are as follows:
Substance S, J/mol•K
Li (s) 29.12
O2 (g) 205.138
H2 (g) 130.68
LiOH (s) 42.8
Li (s) + 0.5 O2 (g) + 0.5 H2 (g) → LiOH (s).
The entropy contents of the reactants and product at 25°C are as follows:
Substance S, J/mol•K
Li (s) 29.12
O2 (g) 205.138
H2 (g) 130.68
LiOH (s) 42.8
Expert's answer
Calculate it using the formula:
∆S = Sproducts - Sreagents
∆S = 42,8 - 65,34 - 102,569 - 29,12 = -154,225 J/mol•K
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