Question

Calculate the entropy change at 25°C for the following reaction:

Li (s) + 0.5 O2 (g) + 0.5 H2 (g) → LiOH (s).

The entropy contents of the reactants and product at 25°C are as follows:

Substance S, J/mol•K

Li (s) 29.12

O2 (g) 205.138

H2 (g) 130.68

LiOH (s) 42.8

Answer 1

Calculate it using the formula:

∆S = S_products - S_reagents

∆S = 42,8 - 65,34 - 102,569 - 29,12 = -154,225 J/mol•K

Have a great day and be healthy :)