Question #105470

Sally heats 54.78g of an unknown hydrate until it is dehydrated. The final mass of the sample is 42.35g. What is the mass of the water that was contained in the hydrate?

Expert's answer

m(water)=m(hydrate)mfinal(sample)=54.78g42.35g=12.43gm(water)= m(hydrate)-m_{final}(sample)= 54.78g-42.35g= 12.43g


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