From the reaction
2NaOH+CO2⟶Na2CO3+H2O,
here NaOH is the titrant and CO2 containing soln with few drops of phenolpthalein the analyte. Aim is the find out the number of moles of CO2 :
n(NaOH)=c(NaOH) × V
n(CO2)=1/2 n(NaOH)
While calculating the number of moles of NaOH required to perform the reaction, We took the conc. of NaOH (in M) and volume of the titrant (which is usually in ml). Shouldn't we convert the ml into l?