Answer to Question #9823 in Inorganic Chemistry for Sharmin Hoque
The solubility of AlCl(3) is 46.6 grams in 100 mL in water. How many grams of AlCl(3) will dissolve in 1.68 L?
1
2012-05-22T10:54:35-0400
1.68 L of water dissolves 46.6*1.68/0.1=782.88 grams of AlCL3.
Need a fast expert's response?
Submit order
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment