Molar mass of the compound 44gm
Let us consider one mole of the compound present in the solution
Among that 54.5% carbon present by weight thus carbon present 23.98gm almost 24 gm thus 2 mol of carbon present
36.4 % oxygen present by weight thus oxygen present16 gm thus 1 mole atomic oxygen present
9.1% hydrogen present by weight = 4.004 gm thus 4 mole atomic oxygen present
Thus empirical formula C2H4O
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