The given reaction is rather obvious to balance. You have to put 2 at KBr and KCl:
Cl2(aq)+2KBr(aq)→Br2(aq)+2KCl(aq)Cl_{2}(aq)+2KBr(aq) \rightarrow Br_{2}(aq)+2KCl(aq)Cl2(aq)+2KBr(aq)→Br2(aq)+2KCl(aq)
It is substitution or single-displacement reaction (A + BC = AC + B).
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