In here Zn(II) is getting converted to Zn.
and Fe is getting converted to Fe(II)
Thus (1) Zn2+ + 2e- = Zn , E= -0.76 V
(2) Fe = Fe (II) + 2e- , E= 0.44
(1) + (2) = E= -0.76+0.44 = -0.22 V
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