Answer to Question #92804 in Inorganic Chemistry for uma

Question

4dm3 of h2s reacts with 10dm3 of o2 at constant presssure and temperature what is the final volume?

Answer 1

2H₂S + 3O₂ = 2H₂O + 2SO₂

H₂S is a limiting reagent and 2 moles of it will burn out in 3 moles of O₂. 3 moles of O₂ is 6 dm³, which means 4 dm³ of oxygen will remain in products as an extra.

By stoichiometry, 2 moles of each product was produced, that means 4 dm³ H₂O and 4 dm³ of SO₂ were produced.

Final volume = 4 dm³ (O₂ not used) + 4dm³ (SO₂) + 4 dm³ (H₂O) = 12 dm³