Cr2O72- + H3O+ + Fe2+ = Cr3+ + Fe3+ + H2O
2Cr+6 + 6e = 2Cr+3 6 1
Fe+2 – 1e = Fe+3 1 6
Therefore, the ionic equation has the form:
Cr2O72- + 14H3O+ + 6Fe2+ = 2Cr3+ + 6Fe3+ + 21H2O
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