Question

If the rate of reaction doubles for every 10 °C rise in temperature, how much faster does
the reaction proceed at 45 °C than at 25 °C? At 95 °C than at 25 °C?

Answer 1

Solution.

$$v2 = v1 \times \gamma ^{\frac{t2-t1}{10}}$$

According to the Vant-Hoff Rule, each time the temperature rises by 10 degrees Celsius, the reaction rate increases by 2 times, then for the first case it will increase by 4 times, and in the second case, by 14 times.

Answer:

1) 4 times

2) 14 times