Answer to Question #90058 in Inorganic Chemistry for Ayilara AbdulQowiyyu

Question #90058
The observed rotation of 2.0g of a compound in a 50ml of solution in a polarimeter tube 20cm long is +138°, what is the specific rotation of the compound?
1
Expert's answer
2019-05-22T07:03:46-0400

Specific rotation is equal to: "[\\alpha]=\\frac{\\alpha}{l\\cdot c}"

where "\\alpha" is the measured rotation in degrees, l is the path length in decimeters, c is the concentration in g/mL. Thus,

"[\\alpha]=\\frac{\\alpha}{l\\cdot c}=\\frac{\\alpha \\cdot V}{l\\cdot m}=\\frac{+138^{\\circ} \\cdot 50 mL}{2dm \\cdot 2.0 g}= +1725^{\\circ}"


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