Question

How much HCL-35% purity is required to dissolve 100 grams of solder (tin 60%, lead-40%)?

Answer 1

Lead in acids does not dissolve

Concentrated hydrochloric acid, especially when heated, easily dissolves tin

Sn + 4HCl = H₂[SnCl₄] + H₂↑

m(Sn) = 0.6 x 100 = 60 gram

119 gram/mol Sn – 4 mol HCl

60 gram Sn – x mol HCl

x = 2.02 mol HCl

m(HCl) = n(HCl) x M(HCl) = 2.02 mol x 36.5 g/mol = 73.73 g

35 g HCl – 100 g solution

73.73 g HCl – x g solution

x = 210.66 g