calculate the number of molecules and number of atoms present in 5.60l of ozone at n.t.p
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Expert's answer
2012-05-08T08:57:46-0400
n = V/22.4 = 0,25 mol
in 1 mol is 6,02x10^23 (Avogadro constant) in 0,25 mol is 1.505x10^23 number of molecules :1.505x10^23 In ozone(O3) are 3 atoms of oxygen,so number of atoms :3*1.505x10^23 =4,515x10^23
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