Question

What is the density of 5 moles of argon at 790 torr and 75 F?

Answer 1

$$\begin{array}{l} 790 \text{ torr} = 105324,671 \text{ Pa} \\ 75 \text{ F} = 23,88^{\circ} \text{C} = 297,04 \text{ K} \end{array}$$ $$\begin{array}{l} pV = nRT \\ pV = \frac{m}{M} RT \\ pM = \frac{m}{V} RT \\ pM = \rho RT \\ \rho = \frac{pM}{RT} = \frac{105324,671 \cdot 0,03995}{8,31 \cdot 297,04} = 1,705 \text{ g/cm}^3 \end{array}$$

Answer: $1,705 \text{ g/cm}^3$