2 PH3 + 8 CL2 = 2 PCL5 + 6 HCL
M(Cl2) = 71 g/mol
M(PCL5) = 208.24 g/mol
M(PH3) = 40.0 g/mol
For equation we can see, that PH3 is an excess. So the calculations are carried out on chlorine.
568 g (CL2) = 416.48 g (PCL5)
15 g (Cl2) = x g (PCL5)
x = 416.48*15/568 = 11.0g (PCL5)
For experiment yield is 5.5g
Percentage yield = 5.5/11.0*100% = 50%
Answer: 50%
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