Question

How many grams of sulfur must be burned (with sufficient oxygen) to produce 5.282 L of sulfur dioxide?

Answer 1

Question # 85514, answer

How many grams of sulfur must be burned (with sufficient oxygen) to produce 5.282 L of sulfur dioxide? ?

Answer:

1) chemical reaction equation

$$S + O2 = SO2$$

2) number of moles of sulfur dioxide SO2 = 5.282 L / 22.4 moles/L = 0.236 moles

3) according to reaction stoichiometry number of moles of sulfur S = 0.236 moles (oxygen is in excess)

4) mass of sulfur = 0.236 moles x 32 g/mole = 7.55 g

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