Question

10cm3 of a solution of hydrochloric acid 6.125g H2SO4 How many moles of H2SO4 are present in 25.0cm3 and what is the concentration of this solution in mol dm-3?

Answer 1

Question #83315, Chemistry / General Chemistry | for completion

10cm3 of a solution of hydrochloric acid 6.125g H2SO4. How many moles of H2SO4 are present in 25.0cm3 and what is the concentration of this solution in mol dm-3?

Solution.

Hydrochloric acid is HCl, not H2SO4. But I will solve this question with HCl and H2SO4.

V1(solution) = 10 cm3 = 0.01 dm3

m(H2SO4) = 6.125 g

V2(solution) = 25 cm3 = 0.025 dm3

n-?

CM-?

Cm = n/V = m/(M*V) = 6.125/(98*0.01) = 6,25 moles/dm3

n for 25 cm3:

n = Cm*V = 6.25*0.025 = 0.156 moles

If acid is HCl, then:

Cm = n/V = m/(M*V) = 6.125/(36,5*0.01) = 16,78 moles/dm3

n for 25 cm3:

n = Cm*V = 16,78*0.025 = 0,4195 moles

Answer:

If H2SO4 is true, then: Cm = 6,25 moles/dm3, n = 0.156 moles.

If HCl is true, then Cm = 16,78 moles/dm3, n = 0.4195 moles

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