Answer on Question #82144, Chemistry/ Inorganic Chemistry
Calculate the heat required to vaporise 7.83 g of benzene at its normal boiling point.
Heat of vaporization (benzene) = 30.7 kJ/mol
Solution
M (C₆H₆) = 78.11 g/mol
n = m / M
n = 7.83 g / 78.11 g/mol = 0.1 mol
Q = ΔHₜₐₚ × n = 30.7 kJ/mol × 0.1mol = 3.07 kJ
Answer: 3.07 kJ
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