Question #82144

Calculate the heat required to vaporize 7.83 g of benzene at its normal boiling point.

Heat of vaporization (benzene) = 30.7 kJ/mol

Expert's answer

Answer on Question #82144, Chemistry/ Inorganic Chemistry

Calculate the heat required to vaporise 7.83 g of benzene at its normal boiling point.

Heat of vaporization (benzene) = 30.7 kJ/mol

Solution

M (C₆H₆) = 78.11 g/mol

n = m / M

n = 7.83 g / 78.11 g/mol = 0.1 mol

Q = ΔHₜₐₚ × n = 30.7 kJ/mol × 0.1mol = 3.07 kJ

Answer: 3.07 kJ

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