Question #80221

Why cu2+ is stable than Au 2+ where as both have d9 configuration

Expert's answer

Answer on Question #80221 – Chemistry – Inorganic Chemistry

Cu2+\mathrm{Cu2+} is stable then Au2+\mathrm{Au2+} , because despite the fact, that they have d9d^9 configuration, its electrons are on the different levels (Cu on 3, Au on 5), that is electronic configuration of Cu2+\mathrm{Cu2+} is 1s22p63s23p63d91s^22p^63s^23p^63d^9 and Au2+\mathrm{Au2+} is 1s22p63s23p63d104s24p64d105s25p65d91s^22p^63s^23p^63d^{10}4s^24p^64d^{10}5s^25p^65d^9 . Charge of Au2+\mathrm{Au^{2+}} higher than Cu2+\mathrm{Cu^{2+}} , but as they are ions, charge density of Au2+\mathrm{Au^{2+}} lower than Cu2+\mathrm{Cu^{2+}} . And it is mean, that Au2+\mathrm{Au^{2+}} worse stabilizes than Cu2+\mathrm{Cu^{2+}} .


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