If volume of mixture co and co2 increases by 20% on passing over hot coke, the percentage of co2 in the oeiginal mixture
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Expert's answer
2018-08-06T07:44:09-0400
Answer: If we have 100 ml CO and CO2, after reaction 120 ml CO (because CO2 + C = 2CO, 100*0.2=120) nCO2=X ml nCO=Y ml CO2+C=2CO 2X-X=20 (because 2-1) X=20 nCO2=20 ml nCO=100-20=80 ml So the percentage of co2 in the oeiginal mixture 80%, because (80*100)/100=80 %
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