Question

For a first order reaction, it takes 37 min for a reactant to decrease to 50% of its initial value. What is the rate constant for the reaction?

Answer 1

Question #78751, Chemistry / General Chemistry

For a first order reaction, it takes 37 min for a reactant to decrease to 50% of its initial value.

What is the rate constant for the reaction?

Solution:

$$\tau_{1/2} = \frac{\ln 2}{k} = \frac{0.693}{k}$$ $$k = \frac{0.693}{\tau_{1/2}} = \frac{0.693}{37*60} \approx 3.1 * 10^{-4} \ [c^{-1}]$$

Answer: $3.1 * 10^{-4} c^{-1}$

Source: https://opentextbc.ca/chemistry/chapter/12-4-integrated-rate-laws/

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