Question #76516

Calculate the ionization energy of hydrogen atom using Bohr’s theory.

Expert's answer

Answer on Question #76516, Chemistry / Inorganic Chemistry

Calculate the ionization energy of hydrogen atom using Bohr's theory.

Solution

To answer this question we should use the equation:


E=hv=hcλE = h v = \frac{h c}{\lambda}


To find 1λ\frac{1}{\lambda} we should use the Rydberg equation:


1λ=R(1nf21ni2)\frac{1}{\lambda} = R_{\infty} \left( \frac{1}{n_f^2} - \frac{1}{n_i^2} \right)


Where R=1.09737316×107m1R_{\infty} = 1.09737316 \times 10^{7} \, \text{m}^{-1},

for hydrogen atom nf=1,ni=n_f = 1, n_i = \infty, then


1λ=R\frac{1}{\lambda} = R_{\infty}


and


E=hv=hcλ=hvRE = h v = \frac{h c}{\lambda} = h v R_{\infty}Ei=6.626×1034×2.997×108×1.09737316×107=2.179×1018(J)E_i = 6.626 \times 10^{-34} \times 2.997 \times 10^{8} \times 1.09737316 \times 10^{7} = 2.179 \times 10^{-18} \, (\text{J})


Answer: 2.179×1018(J)2.179 \times 10^{-18} \, (\text{J})

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