Answer to Question #75314 in Inorganic Chemistry for Meg

Question #75314

Describe how you would prepare a 2.00 L of 0.100 M KrCrO4 from 1.75 M K2CrO4 stock solution

Expert's answer

n (KrCrO4) = 2 * 0.1 = 0.2M
V(1.75 M KrCrO4) = 0.2 /1.75 = 0.114 L

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