Question

Hi there

I have an icp-ms result of 5.6 ug/g scandium. I want to back calculate to how much scandium oxide I initially had in ug/g and kg/ton. Thanks in advance.

Answer 1

Answer on Question #75149, Chemistry / Inorganic Chemistry

I have an icp-ms result of $5.6\ \mathrm{ug/g}$ scandium. I want to back calculate to how much scandium oxide I initially had in $\mathrm{ug/g}$ and $\mathrm{kg/ton}$.

Answer:

$$2 \mathrm{Sc_2O_3} = 4 \mathrm{Sc} + 3 \mathrm{O_2}$$ $$x\ \mathrm{ug/g}\ \mathrm{Sc_2O_3} = \frac{5.9\ \frac{\mathrm{ug}}{\mathrm{g}} \times 137.9\ \frac{\mathrm{g}}{\mathrm{mol}} \times 2}{44.9\ \frac{\mathrm{g}}{\mathrm{mol}} \times 4} = 9.3\ \frac{\mathrm{ug}}{\mathrm{g}}$$

Convert $\mathrm{ug/g}$ to $\mathrm{kg/ton}$

$$\frac{9.3\ \frac{\mathrm{ug}}{\mathrm{g}}}{x\ \frac{\mathrm{kg}}{\mathrm{ton}}} = \frac{1\ \frac{\mathrm{ug}}{\mathrm{g}}}{0.000907185\ \frac{\mathrm{kg}}{\mathrm{ton}}}$$ $$x\ \frac{\mathrm{kg}}{\mathrm{ton}} = \frac{9.3\ \frac{\mathrm{ug}}{\mathrm{g}} \times 0.0009\ \frac{\mathrm{kg}}{\mathrm{ton}}}{1\ \frac{\mathrm{ug}}{\mathrm{g}}} = 0,008\ \frac{\mathrm{kg}}{\mathrm{ton}}$$

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