Question

0.67g of a solution of trioxonitrate 5
acid in 100cm3. 31cm3 of this solution neutralized
25cm3 of sodium trioxocarbonate 4. calculate the
molar concentration of the base and the mass concentration of the base?

Answer 1

n(HNO₃)m/M=0.0106Mol
Cm(HNO₃)=0.0106*1000/100=0.106Mol/L
N(HNO₃)=Cm(HNO₃)=0.106Mol/L
N(Na₂CO₃)=0.13155Mol/L
Cm(Na₂CO₃)=2N(Na₂CO₃)=0.26288Mol/L
n(Na₂CO₃)=0.006572Mol
m(Na₂CO₃)=n*M=0.6966g
W(Na₂CO₃)=0.26288Mol/L
W(Na₂CO₃)=2.786%