Question #66798

write molecular orbital configuration for following molecular ions . commenton paramagnetic properties of these ions -
1 . N2+ and
2 . N2 2-

Expert's answer

Answer on Question #66798 - Chemistry - Inorganic Chemistry

Question:

write molecular orbital configuration for following molecular ions. commenton paramagnetic properties of these ions -

1. N2+ and

2. N2 2-

Solution:


N2+(13e):σ21sσ21sσ22sσ22sπ22pπ22pσ12pN _ {2} + (1 3 e -): \sigma^ {2} 1 s \sigma^ {* 2} 1 s \sigma^ {2} 2 s \sigma^ {* 2} 2 s \pi^ {2} 2 p \pi^ {2} 2 p \sigma^ {1} 2 pN22(16e):σ21sσ21sσ22sσ22sπ22pπ22pσ22pπ12pπ12pN _ {2} ^ {2} - (1 6 e -): \sigma^ {2} 1 s \sigma^ {* 2} 1 s \sigma^ {2} 2 s \sigma^ {* 2} 2 s \pi^ {2} 2 p \pi^ {2} 2 p \sigma^ {2} 2 p \pi^ {* 1} 2 p \pi^ {* 1} 2 p


These ions will have paramagnetic properties. Paramagnets are substances that are magnetized in an external magnetic field in the direction of an external magnetic field and have a positive magnetic susceptibility. The paramagnetic properties of ions are due to the presence of unpaired electrons. N2 + and N2 2- on the orbital have unpaired electrons, that is, these ions have paramagnetic properties.

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