Question #65529

What is the molar concentration of solution of 162.8g of calcium hydroxide dissolved completely in 1000cm cube of distilled water (ca=40,o=16,h=1)

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Answer on Question # 65529 - Chemistry | General Chemistry

What is the molar concentration of solution of 162.8g162.8\mathrm{g} of calcium hydroxide dissolved completely in 1000cm1000\mathrm{cm} cube of distilled water (Ca=40,O=16,H=1)(\mathrm{Ca} = 40, \mathrm{O} = 16, \mathrm{H} = 1)

Solution

m(Ca(OH)2)=162.8 g\mathrm{m}(Ca(OH)_2) = 162.8\ \mathrm{g}V=1000 cm3=1 LV = 1000\ \mathrm{cm}^3 = 1\ \mathrm{L}C=nVC = \frac{n}{V}n=mMn = \frac{m}{M}M(Ca(OH)2)=40+216+21=74 g/mol\mathrm{M}(Ca(OH)_2) = 40 + 2 \cdot 16 + 2 \cdot 1 = 74\ \mathrm{g/mol}n=mM=162.8 g74 gmol=2.2 moln = \frac{m}{M} = \frac{162.8\ \mathrm{g}}{74\ \frac{\mathrm{g}}{\mathrm{mol}}} = 2.2\ \mathrm{mol}C=nV=2.2 mol1 L=2.2 mol/L=2.2 MC = \frac{n}{V} = \frac{2.2\ \mathrm{mol}}{1\ \mathrm{L}} = 2.2\ \mathrm{mol/L} = 2.2\ \mathrm{M}

Answer

The molar concentration must be 2.2 mol/L2.2\ \mathrm{mol/L} or 2.2 M2.2\ \mathrm{M}.


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