Question

if ozone is present in air at the odor threshold and if oxygen is 21% of the air, how many O2 molecules are there per O3 molecules? What is the ratio of O2 to O3 molecules?

Answer 1

Answer on Question #64718, Chemistry / Inorganic Chemistry

if ozone is present in air at the odor threshold and if oxygen is 21% of the air, how many O2 molecules are there per O3 molecules? What is the ratio of O2 to O3 molecules?

Answer

odor threshold – 0,02mkg/L

In 100L air:

m(O₃)=2mkg

n= m/M = 0,0000021 / 48 = 4,2*10⁻⁸ (O₃)

N=n*NA=4,2*10⁻⁸*6,02*10²³=2,53*10¹⁶ O3 molecules., ratio O₂ to O₃:

3O₂=2O₃

$$\frac{3O_2}{x} = \frac{2O_2}{2,53*10^{16}}$$

x= 3*2,53*10¹⁶ / 2 = 3,795*10¹⁶, O2 molecules contained in O3

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