Question

How do you make a liquid 8% solution by volume of NaHCO3 from dry NaHCO3 that is 45% by weight?

Thank you in advance.

Answer 1

Answer on Question #63721 - Chemistry – Inorganic Chemistry

How do you make a liquid 8% solution by volume of NaHCO₃ from dry NaHCO₃ that is 45% by weight?

Solution.

Weight percent = 45%

45 g NaHCO₃ in 100 g solution

ρ(solution) = 1.0581 g/mL

V(solution) = m(solution)/ρ(solution) = 100/1.0581 = 94.5 mL

ρ(NaHCO₃) = 2.2 g/mL

V(NaHCO₃) = m(NaHCO₃)/ρ(NaHCO₃) = 45/2.2 = 20.45 mL

Volume percent = (20.45/94.5)×100% = 21.64%

8% = (20.45/x)×100%

x = 255.6 mL solution

m(H₂O) = 255.6 – 100 = 155.6 mL

Answer: Add to 45% solution of NaHCO₃ 155.6 mL of H₂O

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