Question

what volume of Hydrochloric acid can be used in 25cm3 of Sodium Carbonate

Answer 1

Answer on Question #63229, Chemistry / Inorganic Chemistry

What volume of Hydrochloric acid can be used in $25\mathrm{cm}^3$ of Sodium Carbonate?

Solution:

Balanced equation:

$$\mathrm{Na_2CO_3} + 2\mathrm{HCl} \rightarrow 2\mathrm{NaCl} + \mathrm{H_2O} + \mathrm{CO_2}$$

Molar mass of $\mathrm{Na_2CO_3} = 106\ \mathrm{g\ mol^{-1}}$

$$\begin{array}{l} \rho \left(\mathrm{Na_2CO_3}\right) = 2.54\ \mathrm{g/cm^3} \\ m = \rho V = 25\ \mathrm{cm^3} \times 2.54\ \mathrm{g/cm^3} = 63.5\ \mathrm{g} \\ \end{array}$$

Under normal conditions, the molar volume of any gas is $22.4\ \mathrm{L/mol}$

$$\begin{array}{l} x / 22.4\ \mathrm{L\ mol^{-1}} = 63.5\ \mathrm{g} / 106\ \mathrm{g\ mol^{-1}} \\ x = 63.5\ \mathrm{g} \times 22.4\ \mathrm{L\ mol^{-1}} / 106\ \mathrm{g\ mol^{-1}} = 13.4\ \mathrm{L} = 13400\ \mathrm{cm^3} \\ \end{array}$$

Answer: 13.4 L

https://www.AssignmentExpert.com