Question

Lead (ii) sulphate is used as white pigment.what is the solubility of pbS04?
ksp is 1.8x10_11

Answer 1

Answer on Question #59512, Chemistry / Inorganic Chemistry

1. Lead (II) sulphate is used as white pigment. what is the solubility of $\mathrm{PbSO_4}$? ksp is $1.8 \times 10^{-11}$

Solution:

$$\mathrm{Ksp} \quad \mathrm{PbSO_4} = [\mathrm{Pb^{2+}}][\mathrm{SO_4^{2-}}]$$

S – solubility

$$[\mathrm{Pb^{2+}}] = [\mathrm{SO_4^{2-}}] = \mathrm{S}$$ $$\mathrm{Ksp} = \mathrm{S} \times \mathrm{S} = \mathrm{S^2}$$ $$\mathrm{S} = \sqrt{\mathrm{Ksp}}$$ $$\mathrm{S} = \sqrt{1.8 \times 10^{-11}} = 4.24 \times 10^{-6}$$

Answer: $S = 4.24 \times 10^{-6}$

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