Question #59283

. Calculate the maximum number of mole of Ba3(P O4)2 when 0.6 mole of BaCl2 is mixed
with 0.6 mole of N a3P O4.

Expert's answer

Question # 59283, Chemistry / Inorganic Chemistry | for completion

. Calculate the maximum number of mole of Ba3(PO4)2 when 0.6 mole of BaCl2 is mixed with 0.6 mole of N a3PO4.

Answer

0.6 mole 0.6 mole x mole


3BaCl2+2Na3PO4Ba3(PO4)2+6NaCl3BaCl_2 + 2Na_3PO_4 \rightarrow Ba_3(PO_4)_2 + 6NaCl


3 mole 2 mole 1 mole

BaCl₂ – excess

Na₃PO₄ – shortage


v(Ba3(PO4)2)=0.612=0.3 molev(Ba_3(PO_4)_2) = \frac{0.6 \cdot 1}{2} = 0.3 \text{ mole}

Answer: $v(Ba_3(PO_4)_2) = 0.3$ mole

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